30=16t^2+130t+70

Solution for 30=16t^2+130t+70 equation:

30=16t^2+130t+70

We move all terms to the left:

30-(16t^2+130t+70)=0

We get rid of parentheses

-16t^2-130t-70+30=0

We add all the numbers together, and all the variables

-16t^2-130t-40=0

a = -16; b = -130; c = -40;
Δ = b2-4ac
Δ = -1302-4·(-16)·(-40)
Δ = 14340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14340}=\sqrt{4*3585}=\sqrt{4}*\sqrt{3585}=2\sqrt{3585}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-130)-2\sqrt{3585}}{2*-16}=\frac{130-2\sqrt{3585}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-130)+2\sqrt{3585}}{2*-16}=\frac{130+2\sqrt{3585}}{-32}
$